暂无测试数据。

Background

Special for beginners, ^_^

Description

Given two integers x and y, print the sum.

Format

Input

Two integers x and y, satisfying 0 <= x, y <= 32767.

Output

One integer, the sum of x and y.

Sample 1

Input

123 500

Output

623

Limitation

1s, 1024KiB for each test case.

Hint

Free Pascal Code

var a,b:longint;
begin
    readln(a,b);
    writeln(a+b);
end.

C Code

#include <stdio.h>
int main(void)
{
    int a, b;
    scanf("%d%d", &a, &b);
    printf("%d\n", a + b);
    return 0;
}

C++ Code

#include<cstdio>
using namespace std;
int main()
{
    int ptcd=0,k,lptcd=0,n;
    scanf("%d",&k);
    int a[k];
    for(int i=0;i<k;i++)
    {
        scanf("%d",&a[i]);
        if(a[i]==n)
            ptcd++;
        else
        {
            if(ptcd>lptcd)
                lptcd=ptcd;
            n=a[i];
            ptcd=1;
        }
    }
    printf("%d",lptcd);
    return 0;
}

Python Code

a, b = [int(i) for i in raw_input().split()]
print(a + b)

Java Code

import java.io.*;
import java.util.Scanner;

public class Main {

    /**
     * @param args
     * @throws IOException 
     */
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        System.out.println(a + b);
    }
}

Source

Vijos Original