program jiafa;

var

x,y:longint;

begin

read(x,y);

y:=y+x;

writeln(y);

end.

program Plus;

count x,y:real;

begin

read(x,y);

write(x+y);

end.

program Plus;

var x,y:integer;

begin

readln(x,y);

writeln(x+y);

end.

#include

int b,a;

main()

{

scanf("%d %d",&a,&b);

printf("%d",a+b);

}

program P1000;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

wusu5545你太..偶像^_^

maolaoda

此题实质上非常复杂 全面考察到了数学史和计算机史 经典代数 常用计算与输入输出等等等等知识点

考虑到题目的所有可能性 我们应当从计算机存储的二进制的角度来逐步考虑数的表示 以字节计数，采用多字节合用的方式表示一个大整数如今已经是高级程序语言编译器轻松可以达到的目标 可是为了加强对计算机计数的了解 此题可以考虑仍以最原始的方式进行计算——并且考虑最终将二进制数转变为十进制输出的全部过程 期间还考察了对ASCII码的熟悉程度

此题实在经典 乃居家旅行必备之良题

( 2006-3-19 21:00:44 )

wusu5545

牛~~~~

var a,b:integer;

read(a,b);

write(a+b);

end.

program p1000;

var

a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

啊！奇迹啊！

多少天了？多少风雨了？多少历史变迁了？

我终于可以名正言顺的AC了...

program Plus;

var a,b:integer;

begin

read(a,b);

writeln(a+b);

end.

program Plus;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program Plus;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program 1;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

#include

void main()

{

int a,b;

scanf("%d%d",&a,&b);

printf("%d",a+b);

}

#include

int main()

{

int a,b;

scanf("%d%d",&a,&b);

printf("%d",a+b);

return 0;

}

program Plus;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program Plus;

var

a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program Plus;

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program plue

var a,b,k:longint;

begin

readln(a,b);

k:=a+b;

write(k);

end.