7 条题解
- 
  2
马佳艺 LV 8 @ 2017-10-31 12:21:07
-*- coding: utf-8 -*-
"""
Spyder EditorThis is a temporary script file.
"""import math
a=int(input())
b=a/3.1415
c=math.sqrt(b)
print(round(c,3)) - 
  1@ 2019-10-25 16:33:14
print(round((int(input())/3.1415)**0.5,3)) #python3一行代码解决问题(smirk
 - 
  1@ 2019-04-15 20:27:11
import math
n=int(input())
r=math.sqrt(n/3.1415)
print(round(r,3))
#python3 - 
  1@ 2018-11-07 13:23:19
#include <stdio.h> #include<cmath> #include<iostream> using namespace std; double n; int main() { cin>>n; printf("%.3f",sqrt(n/3.1415)); return 0; } - 
  0@ 2023-06-19 22:08:27
import math;print(round(math.sqrt((eval(input())/3.1415)),3))
 - 
  0@ 2023-06-16 23:26:32
s=int(input())
r=(s/3.1415)**0.5
print(round(r,3)) - 
  0@ 2022-05-24 17:39:53
import math
s=int(input("请输入圆的面积:"))
r=math.sqrt(s/3.1415)
print("圆的半径为",round(r,2)) 
- 1
 
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