怎么只过三个点?

var n,i,j,t:integer;

max:int64;

st:string;

a:array[0..101] of string;

b:array[0..101] of integer;

procedure aa(st:string; i:integer);

var x,y,z,p,c,sum:integer;

st1,st2:char;

m:string;

begin

p:=pos(' ',st); m:=copy(st,1,p-1); delete(st,1,p); a[i]:=m;

p:=pos(' ',st); m:=copy(st,1,p-1); delete(st,1,p); val(m,x,c);

p:=pos(' ',st); m:=copy(st,1,p-1); delete(st,1,p); val(m,y,c);

st1:=st[1];

st2:=st[3];

delete(st,1,4);

val(st,z,c);

sum:=0;

if (x>80)and(z>0) then sum:=sum+8000;

if (x>85)and(y>80) then sum:=sum+4000;

if (x>90) then sum:=sum+2000;

if (x>85)and(st2='Y') then sum:=sum+1000;

if (x>80)and(st1='Y') then sum:=sum+850;

b[i]:=sum; max:=max+sum;

end;

begin

readln(n);

for i:=1 to n do

begin

readln(st);

aa(st,i);

end;

for i:=1 to n-1 do

for j:=n downto i+1 do

if (b[j]>b[j-1])or(b[j]=b[j-1])and(a[j]

1 条评论

  • @ 2025-07-11 22:18:44

    用c++更省事

    #include<iostream>
    #include<cstring>
    using namespace std;
    int main()
    {
        int n,i,zq=0,q=0,chengji1,chengji2,lunwen=0,maxn=0,t=0,j;
        char yes=0,yes1=0;
        string name[100];
        cin>>n;
        for(i=0;i<n;i++)
        {
            cin>>name[i]>>chengji1>>chengji2>>yes>>yes1>>lunwen;
            q=0;
            if(chengji1>80&&lunwen>0)
            {
                zq+=8000;
                q+=8000;
            }
            if(chengji1>85&&chengji2>80)
            {
                zq+=4000;
                q+=4000;
            }
            if(chengji1>90)
            {
                zq+=2000;
                q+=2000;
            }
            if(chengji1>85&&yes1=='Y')
            {
                zq+=1000;
                q+=1000;
            }
            if(chengji2>80&&yes=='Y')
            {
                zq+=850;
                q+=850;
            }
            if(q>maxn)
            {
                maxn=q;
                t=i;
            }
        }
        cout<<name[t]<<"\n"<<maxn<<"\n"<<zq;
        return 0;
    }
    
  • 1

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