想不透的0分

program aa;

var

s1,s2:string;

s:array[0..1000]of string;

e:array[0..1000]of integer;

a,c,b,f,t,n,x,d,k:integer;

i,j:char;

begin

readln(n);

for x:=1 to n do

begin

readln(s1);

while s1' ' do

begin

b:=b+1;

s[x]:=s[x]+s1;

end;

b:=b+1;

while s1' ' do

begin

a:=ord(s1)-48+a*10;

b:=b+1;

end;

b:=b+1;

while s1' ' do

begin

c:=ord(s1)-48+c*10;

b:=b+1;

end;

b:=b+1;

i:=s1;

b:=b+2;

j:=s1;

b:=b+2;

d:=ord(s1)-48+d*10;

if (a>80) and (d>=1) then e[x]:=e[x]+8000;

if (a>85) and (c>80) then e[x]:=e[x]+4000;

if a>90 then e[x]:=e[x]+2000;

if (a>85) and (j='Y') then e[x]:=e[x]+1000;

if (c>80) and (i='Y') then e[x]:=e[x]+850;

b:=0;

a:=0;

c:=0;

d:=0;

k:=k+e[x];

end;

for x:=1 to n do

if e[x]>f then

begin

f:=e[x];

s2:=s[x];

end;

writeln(s2);

writeln(f);

write(k);

end.

到底哪里错了,还请大家帮我看看!

3 条评论

  • @ 2009-08-22 12:34:41

    弄不懂

  • @ 2009-08-21 21:54:20

    我也0分YEAH!!

    program scholar;

    var

    name:array[1..100]of string;

    ave,cla,money:array[1..100]of integer;

    bg,bw,m:char;

    ss:char;

    b1,b2,b3:array[1..100]of byte;

    n,i,j,Sum,max,po:integer;

    begin

    fillchar(b1,sizeof(b1),0);

    fillchar(b2,sizeof(b2),0);

    fillchar(b3,sizeof(b3),0);

    fillchar(money,sizeof(money),0);

    Sum:=0;

    max:=0;

    readln(n);

    for i:=1 to n do

    begin

    repeat

    read(ss);

    name[i]:=name[i]+ss;

    until ss=' ';

    read(ave[i],cla[i]);

    read(ss);read(ss);

    if ss='Y' then b1[i]:=1;

    read(ss);read(ss);

    if ss='Y' then b2[i]:=1;

    read(ss);read(ss);

    if (ss'0') then b3[i]:=1;

    readln;

    end;

    for i:=1 to n do

    begin

    if (ave[i]>80) and (b3[i]=1) then money[i]:=money[i]+8000;

    if (ave[i]>85) and (cla[i]>80) then money[i]:=money[i]+4000;

    if (ave[i]>90) then money[i]:=money[i]+2000;

    if (ave[i]>85) and (b2[i]=1) then money[i]:=money[i]+1000;

    if (cla[i]>80) and (b1[i]=1) then money[i]:=money[i]+850;

    Sum:=Sum+money[i];

    if money[i]>max then

    begin

    max:=money[i];

    po:=i;

    end;

    end;

    writeln(name[po]);

    writeln(max);

    writeln(Sum);

    end.

  • @ 2009-08-19 15:57:55

    你的s1应定为char类型

  • 1

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