#include <iostream>
#include <cmath>
#include <stdio.h>
using namespace std;
int main(){
int a,b;
cin>>a>>b;
cout<<a+b<<endl;
system("pause");
return 0;
}

其实可以随机函数 设置种子那里....处理一下

评测结果
VijosEx via JudgeDaemon2/13.7.4.0 via libjudge

编译成功

测试数据 #0: Accepted, time = 0 ms, mem = 732 KiB, score = 10

测试数据 #1: Accepted, time = 0 ms, mem = 728 KiB, score = 10

测试数据 #2: Accepted, time = 0 ms, mem = 728 KiB, score = 10

测试数据 #3: Accepted, time = 0 ms, mem = 728 KiB, score = 10

测试数据 #4: Accepted, time = 0 ms, mem = 732 KiB, score = 10

测试数据 #5: Accepted, time = 0 ms, mem = 728 KiB, score = 10

测试数据 #6: Accepted, time = 0 ms, mem = 732 KiB, score = 10

测试数据 #7: Accepted, time = 0 ms, mem = 732 KiB, score = 10

测试数据 #8: Accepted, time = 0 ms, mem = 732 KiB, score = 10

测试数据 #9: Accepted, time = 0 ms, mem = 732 KiB, score = 10

Accepted, time = 0 ms, mem = 732 KiB, score = 100

纪念一下

其实（a+b）应该保存成**long**型的吧。。。
以此纪念重归vijos通过第一题~

...........................................

program Plus;
var a,b:longint;
begin
readln(a,b);
writeln(a+b);
end.

###高精度。。。
#include<iostream>
#include<cstdlib>
#include<cstdio>
using namespace std;
#define max 1000
char s1[max+10],s2[max+10];
int a[max+10],b[max+10],ans[max+10],p;
int main()
{
int i,j=0,len,t,t2,len2;
for(i=0;i<=max;i++) {a[i]=0; b[i]=0;}
cin>>s1>>s2;
for(i=strlen(s1);i>=0;i--,j++) {a[j]=s1[i]-'0';}
j=0;
for(i=strlen(s2);i>=0;i--,j++) {b[j]=s2[i]-'0';}
len=strlen(s1); len2=strlen(s2);
if(len>len2) t=len;
else t=len2;
for(i=1;i<=t;i++) ans[i]=a[i]+b[i];
for(p=1;p<=t;p++) if(ans[p]>9) {ans[p+1]++; ans[p]=ans[p]%10;}
for(i=t;i>=1;i--) cout<<ans[i];
return 0;
}
###速度快了一点

#include

int main()

{

int a,b,s;

do{

scanf("%d%d",&a,&b);}

while(a32767||b32767);

s=a+b;

printf("%d",s);

return 0;

}

program n (input,output);

var

a,b,c: integer;

begin

read(a,b);

c:=a+b;

write(c);

end.

#include "stdio.h"

main()

{int a,b,sum;

scanf("%d%d",&a,&b);

sum=a+b;

printf("sum=%d",sum);

}

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

#include"stdio.h"

int main()

{

int x,y,sum;

scanf("%d%d",&x,&y);

sum=x+y;

printf("%d\n",sum);

return 0;

}

C99标准解法~

#include

main()

{

int x,y,z;

scanf("%d %d",&x,&y);

z=x+y;

printf("%d",z);

}

var x,y,s:longint;

begin

read(x,y);

s:=x+y;

write(s);

end.

#include“stdio.h”

#include“stdlib.h”

int main(){

int a,b;

scanf("%d %d",&a,&b);

printf("%d",a+b)

}

var a,b:integer;

begin

read(a,b);

write(a+b);

end.

program byc1;

var a,b,sum:integer;

begin

read(a,b);

sum：=a+b;

writeln(sum);

end.

var

a,b,c:longint;

begin

readln(a,b);

c:=a+b;

write(c);

end.

program hu;

var a,b,c:integer;

begin

read(a,b);

c:=a+b；

write(c);

end.

var yu,math,eng,num,s:array[1..300] of integer;

n,i,max,ms,a:integer;

begin

read(n);

for i:=1 to n do

begin

readln(yu[i],math[i],eng[i]);

num[i]:=i;

s[i]:=yu[i]+math[i]+eng[i];

end;

for a:=1 to 5 do

begin

max:=0; ms:=0;

for i:=1 to n do

begin

if max