A+B It's So Easy

#include

int main()

{

int a,b;

long sum;

scanf("%d %d",&a,&b);

sum=a+b;

printf("%ld",sum);

return 0;

}

这题还用题解吗？

include

long a;long ps();

void pl()

{exit (0);}

void pp()

{printf("%d\n",ps()+ps());}

long pa()

{scanf("%d",&a);

return (a);}

long ps()

{return (pa());}

int main()

{pp();pl();}

vijos就是比tyvj好啊！

这东西tyvj无法编译

var a,b,s:longint;

begin

readln(a,b);

s:=a+b;

writeln(s);

end.

也不难，自己去想

读入a，b 直接输出a+b

为了防止卡评测机关掉这题

这样不好吧、

又不是只有这道题可以卡评测机。。

program Tian_lxt;

var

a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program a+b(input,output);

var

a,b:longint;

begin

readln(a,b);

write('a+b=',a+b);

readln;

end.

program a+b(input,output);

var

a,b:longint;

begin

readln(a,b);

write('a+b=',a+b);

readln;

end.

#include

using namespace std;

int main ()

{

int a,b;

cin>>a>>b;

cout

program exp;

var

a,b:longint;

begin

readln(a,b);

writeln(a+b);

readln;

end.

program a+b(input,output);

var

a,b:longint;

begin

readln(a,b);

write('a+b=',a+b);

readln;

end.

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

var a,b:longint;

begin

readln(a,b);

writeln(a+b);

end.

program ab;

var

a,b:integer;

begin

read(a,b);

writeln(a+b);

end.

program ab;

var

a,b:integer;

begin

read(a,b);

writeln(a+b);

end.

#include

using namespace std;

int main ()

{

int a,b;

cin>>a>>b;

cout

话说我是200N年才做出来的……现在才写题解……

var a,b:integer;

begin

read(a,b);

writeln(a+b);

end.

为了保险还可以用longint、int64等类型