3

2351599120 LV 9 @ 2017-07-22 17:21:08

#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
using namespace std;
int main()
{
int a,b=0;
scanf("%d",&a);
while(a!=0)
{
b=10*b+a%10;
a/=10;
}
printf("%d",b);
return 0;
}

2

aph。 (chenqianrong) LV 10 @ 2021-08-29 17:10:35

#include<bits/stdc++.h>
using namespace std;
long long s[11] = {},n,k = 0,a = 1;
int main()
{
    memset(s,0,sizeof(n));
    cin>>n;
    for(int i = 1;i <= 10;i++) s[i] = n/a%10,a *= 10;
    a=1000000000;
    for(int i = 1;i <= 10;i++) k += s[i] * a,a /= 10;
    while(k % 10 == 0) k /= 10;
    cout<<k;
    return 0;
}

1

Infinity_ LV 7 @ 2024-08-26 19:32:15

#include<iostream>
#include<string>
using namespace std;
string s;
int main(){
    ios::sync_with_stdio(false);
    getline(cin, s);
    bool flag = 0;
    if(s[0] == '0'){
        cout << '0';
        return 0;
    }else if(s[0] == '-'){
        cout << '-';
        flag = 1;
    }
    int len = s.size() - 1;
    while(s[len] == '0')len--;
    for(int i = len;i >= flag; i--)cout << s[i];
    return 0;
}

1

SinYita LV 8 @ 2017-11-25 10:46:50

对于0xx 可以先把结果存储在新变量中最后输出该变量如果需要0的话就用以0占位的方式 %0xd

#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
    int a,b=0;
    scanf("%d",&a);
    while(a!=0)
    {
        b=b*10+a%10;
        a/=10;
    }
    printf("%d",b);
    return 0;
}

1

dusk LV 8 @ 2017-10-22 09:05:01

#include<stdio.h>
int n,s=0;
int main()
{
scanf("%d",&n);
if(n<0)
{
printf("-");
n=-n;
}
while (n!=0)
{
s=s*10+n%10;
n=n/10;
}
printf("%d\n",s);
return 0;

}

dusk @ 2017-10-22 09:05:55

H2O的一道题

1

任展烨 LV 8 @ 2017-10-20 22:42:08

var
s,x:string;
c,i:longint;
begin
readln(s);x:='';
if s[1]='-' then begin
for i:=length(s) downto 2 do x:=x+s[i];
val(x,c);writeln('-',c);
end
else begin
for i:=length(s) downto 1 do x:=x+s[i];
val(x,c);writeln(c);
end;
end.

1

Galileonardo LV 7 @ 2017-10-04 21:40:17

char类型读入倒读搞定。
#include <iostream>
using namespace std;

char arr[10];
int i=0;
char a;
bool truefalse=false;

int main() {
a=getchar();
if(a!='-'){
while(a!='\n'){
arr[i]=a;
a=getchar();i++;
}
}else{
truefalse=true;
a=getchar();
while(a!='\n'){
arr[i]=a;
a=getchar();i++;
}
}
if(truefalse==true){
cout<<'-';truefalse=false;
}
int number=0;
for(int j=i-1;j>=0;j--){
if(number==0){
if(arr[j]!='0'){
cout<<arr[j];number=1;truefalse=true;
}
}else{
cout<<arr[j];
}
}
if(truefalse==false){
cout<<0;
}
return 0;
}

1

猫粮寸断 LV 10 @ 2017-09-21 15:27:46

第一遍想错了N的范围
把数组开到了1000000000
但是居然AC了
仔细一看题发现并不需要
2333

#include<cstring>
using namespace std;
char c[100];
int main()
{
    int num,i,flag=0;
    cin>>c;
    num=strlen(c);
    if(c[0]=='-')
     {
      cout<<"-";
      for(i=num-1;i>0;i--)
      {
        if(!flag)
        {
            if(c[i]=='0')
            continue;
            else
            {
                flag=1;
                cout<<c[i];
            }
        }
        else
        cout<<c[i];
      }
     }
     else
     for(i=num-1;i>=0;i--)
      {
        if(!flag)
        {
            if(c[i]=='0')
            continue;
            else
            {
                flag=1;
                cout<<c[i];
            }
        }
        else
        cout<<c[i];
      }
    return 0;
}

0

SinYita LV 8 @ 2017-11-25 10:47:26

#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
    int a,b=0;
    scanf("%d",&a);
    while(a!=0)
    {
        b=b*10+a%10;
        a/=10;
    }
    printf("%d",b);
    return 0;
}

0

KNO3 LV 8 @ 2017-11-04 20:00:46

直接模拟

pascal
cpp var s:int64; f:boolean; //标志开头的0是否已完 begin read(s); if s=0 then begin write(0);exit;end; //特殊情况的处理 if s<0 then write('-'); s:=abs(s); //处理负数 while s>0 do begin if (s mod 10 <>0)or(f) then begin f:=true;write(s mod 10);end; s:=s div 10; end; end.

0

Little Black LV 7 @ 2017-10-01 09:06:50

500 3
150 300
100 200
470 471

0

吴哥——传奇 LV 8 @ 2017-08-22 02:47:52

so water

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <cstring>
#include <algorithm>
using namespace std;
int main()
{
    char a[10000]={0},w,i=0,n=1,e=0;
    w=getchar();
    while(w!='\n'&&w!=EOF&&w!='\0')
    {
        if(i==0&&w=='-')
            printf("-");
        else
        {
            i++;
            a[i]=w;
        }
        w=getchar();
    }
    n=i;
    for(i=n;i>=1;i--)
    {
        if(e!=0||a[i]!='0')
        {
            e=1;
            printf("%c",a[i]);
        }   
    }
    return 0;
}

0

李暑涵 LV 8 @ 2017-07-17 09:43:48

Accepted

/usr/bin/ld.bfd: warning: /out/link.res contains output sections; did you forget -T?

状态耗时内存占用

#1 Accepted 1ms 256.0KiB
#2 Accepted 1ms 256.0KiB
#3 Accepted 1ms 256.0KiB
#4 Accepted 1ms 256.0KiB
#5 Accepted 1ms 256.0KiB
#6 Accepted 1ms 256.0KiB
#7 Accepted 1ms 256.0KiB
#8 Accepted 1ms 184.0KiB
#9 Accepted 1ms 256.0KiB
#10 Accepted 1ms 256.0KiB
代码

var
s,x:string;
c,i:longint;
begin
readln(s);x:='';
if s[1]='-' then begin
for i:=length(s) downto 2 do x:=x+s[i];
val(x,c);writeln('-',c);
end
else begin
for i:=length(s) downto 1 do x:=x+s[i];
val(x,c);writeln(c);
end;
end.

0

JimmyChen LV 8 @ 2017-07-07 16:49:02

#include <cstdio>
#include <iostream>

using namespace std;

int main(){
    int num = 0;
    bool sign = false;
    cin >> num;
    if (num < 0) sign = true;
    int result = 0;
    while (num != 0){
        int last = num % 10;
        result = result * 10 + last;
        num /= 10;
    }
    //if (sign) result *= -1;
    cout << result << endl;
}

0

142857 LV 8 @ 2017-01-12 17:26:41

#include<stdio.h>

int main()
{
int n,ans=0;
scanf("%d",&n);
while(n)
{
ans*=10;
ans+=n%10;
n/=10;
}
printf("%d",ans);
return 0;
}

0

gg_c LV 7 @ 2016-12-19 19:24:55

哈哈 Ac了
#include<stdio.h>
#include<string.h>
int main()
{
char sh[11];
scanf("%s",sh);
int len = strlen(sh);
int i;
if(sh[0] == '-')
{
printf("-");
}
if(sh[0] == '0')
{
printf("0");
return 0;
}
int sign = 0;
for(i=len-1; i >= 0; i--)
{
if(sh[i] != '0')
{
sign = 1;
}
// printf("i = %d sign = %d\n",i,sign);
if(sh[i] != '-'&&sign == 1)printf("%c",sh[i]);

}
return 0;
}

0

dglyy LV 7 @ 2016-12-19 17:58:55

评测结果
编译成功

Free Pascal Compiler version 3.0.0 [2015/11/16] for i386
Copyright (c) 1993-2015 by Florian Klaempfl and others
Target OS: Win32 for i386
Compiling foo.pas
Linking foo.exe
29 lines compiled, 0.0 sec, 26512 bytes code, 1268 bytes data
测试数据 #0: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #1: Accepted, time = 0 ms, mem = 812 KiB, score = 10
测试数据 #2: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 812 KiB, score = 10
测试数据 #4: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #6: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #8: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 808 KiB, score = 10
Accepted, time = 0 ms, mem = 812 KiB, score = 100
代码
var t:char;
s:string;
o,i,f:longint;
fs:boolean;
begin
read(s);
if s[1]='-' then
begin
fs:=true;
delete(s,1,1);
end;
o:=length(s)+1;
f:=length(s) div 2;
for i:=1 to f do
begin
t:=s[i];
dec(o);
s[i]:=s[o];
s[o]:=t;
end;
for i:=1 to length(s)+1 do
begin
if s[1]<>'0' then break;
if s[1]='0' then delete(s,1,1);
end;
if fs then write('-');
write(s);

end.

0

ZGZZN LV 8 @ 2016-11-18 15:54:22

#include<bits/stdc++.h>
using namespace std;
char a[1000];
int main()
{
int i,j,k,n,m;
cin>>a;
n=strlen(a);
if(a[0]=='-')
{
cout<<a[0];
for(i=n-1;i>0;i--)
{
if(a[i]!='0')
{
k=i;
break;
}
}
for(i=k;i>0;i--)
cout<<a[i];
}
else
{
for(i=n-1;i>=0;i--)
{
if(a[i]!='0')
{
k=i;
break;
}
}
for(i=k;i>=0;i--)
cout<<a[i];
}
return 0;
}

0

我是xxx LV 8 @ 2016-11-01 18:45:36

不明白为什么要用字符处理
#include<cstdio> int n; main() { scanf("%d",&n); if(n<0){printf("-");n*=-1;} while(n%10==0) n/=10; while(n!=0) { printf("%d",n%10); n/=10; } }

0

各种up LV 8 @ 2016-10-05 14:36:11

Free Pascal Compiler version 3.0.0 [2015/11/16] for i386
Copyright (c) 1993-2015 by Florian Klaempfl and others
Target OS: Win32 for i386
Compiling foo.pas
Linking foo.exe
20 lines compiled, 0.0 sec, 26592 bytes code, 1268 bytes data
测试数据 #0: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #1: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #2: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #4: Accepted, time = 15 ms, mem = 808 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #6: Accepted, time = 0 ms, mem = 804 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 808 KiB, score = 10
测试数据 #8: Accepted, time = 0 ms, mem = 812 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 808 KiB, score = 10
Accepted, time = 15 ms, mem = 812 KiB, score = 100
代码
```pascal
var a,t:longint;
inp:char;
fs:boolean;

begin
fs:=false;
read(inp);
if inp='-' then begin
a:=0;t:=1;fs:=true;
end else begin
a:=ord(inp)-ord('0');t:=10;
end;
while not eoln do begin
read(inp);
inc(a,(ord(inp)-ord('0'))*t);
t:=t*10;
end;
if fs then write('-');
writeln(a);
end.
```

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题解

73 条题解

状态 耗时 内存占用

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状态耗时内存占用